Concepts Practice Questions Important Formulas If the simple interest on Re.1 for 1 month is 1 paisa, then the rate percent per annum will be 8 6 10 12 View Answer Answer is d  2. The amount to be paid, when principle = Rs.2000, rate of simple interest R = 5 Rs. 2400 Rs. […]
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In a test, Â for each correct answer, 1 mark is awarded and one mark is deducted for each wrong answer. When a boy answers all 20 items of the test and gets 8 marks, the number of questions answered correctly by him was 14 8 16 12 Answer is a 2. The sum of
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The sum of a non-zero number and thrice its reciprocal is 52/7. Find the number. 9 6 7 8 Answer is c 2. A fraction is greater than its reciprocal by 9/20. What is the fraction?  4/5 4/3 3/4 5/4 Answer is d  3. 7, 77, 77, 77777 ÷ 77 equals 101001 1010101
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When a man spends 1/3 of his income on food, 2/5 of his income on clothes. Now, if he still has ₹400 left with him. His income is ₹ 5000 ₹ 7000 ₹ 4000 ₹ 6000 Answer is d 2. By how much does 6/(7/8) exceed (6/7)/8 ?  6 × (3/4) 7 × (5/6)
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In a class, 3/5 of the students are girls, and the rest are boys. When 2/9 of the girls and1/4 of the boys are absent. What part of the total number of students are present? 23/36 17/25 23/30 18/49 Answer is c 2. Half of 1 percent written as a decimal is  0.02 0.005
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Arrangement of the fractions into 4/3, -2/9, -7/8, 5/12 ascending order is -7/8, -2/9, 4/3, 5/12 -2/9, -7/8, 4/3, 5/12 -7/8, -2/9, 5/12, 4/3 -2/9, -7/8, 5/12, 4/3 Answer is c 2. The greatest among the following numbers ³√3, √2, 1, 6root 6 is  1 6root 6 ³√3 √2 Answer is c  3.
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The sum of three consecutive odd natural numbers is 147. Then, the middle number is 48 51 49 47 Answer is c 2. The sum of all natural numbers between 100 and 200. Which are multiples of 3 is  4900 4950 4980 5000 Answer is b  3. The sum of the squares of
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The sum of all prime numbers between 58 and 68 is 178 183 179 187 Answer is d 2. The sum of three consecutive odd numbers is always divisible by  9 21 3 15 Answer is c  3. Arrange the following fractions in decreasing order 3/5, 7/9, 11/13 7/9, 3/5, 11/13 11/13, 3/5,
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For a two-digit number, the digit which is at the unit’s place is 1 less than twice the digit at the ten’s place. When the digits at unit’s and ten’s place are interchanged, the difference between the new and the original number is less than the original number by 20. Then, the original number
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When the number x is divided by a divisor it’s seen that the divisor = 4 times the quotient = double the remainder. If the remainder is 80 then the worth of x is  9680 8460 6480 4680 Answer is c From the question Divisor=4 × Quotient = 2 × reminder Given reminder =
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